00:01
In this problem, we have a pulley supporting a mass with two separate ropes.
00:06
We're given the mass and the direction of one of the ropes, and we're asked to find what force the magnitude and direction will have to apply to the second rope to maintain our mass in equilibrium.
00:25
And the first thing we can do is looking at a free body diagram of our our mass, we can say that t1 equals to mg and our m was 640 kilograms.
00:41
So we have t1 equals 640g.
00:45
And then we can look at our pulley and some forces in the x and y direction and set them equal to 0.
00:59
And in the x direction, we will have a t1 cosine 60 minus a t2 cosine unknown theta 2.
01:15
In the y direction, we have a t1 sine 60 plus t2 sine theta 2 minus a t1.
01:32
And we can sub in our t1 equals 640g and rearrange these equations.
01:42
So we're left with, for the x, t2 cosine theta 2 equals 640g cosine 60.
01:55
And for the y, we get a t2 of sine theta 2 equals 640g times 1 minus sine 60...