00:01
What are the magnitude and direction of the net gravitational force? so for part a, let's write our expression for our gravitational force, which is g mass 1 mass 2 over radius squared.
00:17
Now let's find it first due to our 5 kg mass.
00:22
We plug in g, 20 times 5, times our distance of 0 .2 squared.
00:28
We get 1 .67 times 10 to the negative 7 newtons in the vertical direction.
00:38
Due to our 10 kg mass, we get 1 .34 times 10 to the negative 6 newtons.
00:47
Then our magnitude of our net force is the square root of f1 squared plus f2 squared.
00:54
We get 1 .35 times 10 to the negative 6 newtons.
00:59
Now we can find the direction of our net force.
01:04
That's the inverse tangent of our 1 .67 times 10 to the negative 7 over 1 .34 times 10 to the negative 6.
01:14
We get 82 .9 degrees from the positive y -axis.
01:22
For b, we like to find it on the 5 kg mass...