00:01
A position and a velocity as a function of time in simple harmonic motion.
00:06
X as a function of time equaling a cosine of omega -t, the angular frequency multiplied by time plus the phase constant, phi -not.
00:16
And we have the velocity in the x -direction as a function of time, equaling the negative amplitude multiplied by the angular frequency, multiplied by sine of omega -t, finite this is also equaling the negative maximum velocity multiplied by sine of omega t plus finite and so here we know that from the graph t equals 12 seconds and so the angular frequency would be equaling to 2 pi over the period t this is equaling to 2 pi over 12 seconds and we find that then the angular frequency is equaling to pi over six radians per second.
01:04
For part a, we know the maximum velocity is equaling the product of the amplitude and the angular frequency, and we know that this is equaling then 60 centimeters per second.
01:16
And so the amplitude then would be equaling the maximum velocity divided by the angular frequency.
01:23
This would be equaling than 60 centimeters per second divided by pi over six radians per second.
01:31
And this is giving us approximately 115 centimeters or we can say 1 .15 meters.
01:42
For part b we have t equaling zero seconds and so we can say that the initial velocity in the x direction would be equaling to negative a omega sign of finite this is going to then equal negative 30 centimeters per second and so we can say then that negative 60 centimeters per second, the maximum velocity, multiplied by sine of phi not equals negative 30 centimeters per second.
02:24
And so we can say that then phi not is equaling arc sign of 1⁄2 or 0 .5 radians...