Question
Figure shows four batteries of emf $E$ and internal resistance ' $r^{\prime}$ are connected in series. The voltage across each battery is:(a) $2 \mathrm{~V}$(b) $0 \mathrm{~V}$(c) $1.5 \mathrm{~V}$(d) $0.75 \mathrm{~V}$
Step 1
Since the four batteries are connected in series, the equivalent emf is the sum of the emf of each battery and the equivalent resistance is the sum of the resistance of each battery. Therefore, we have: \[E_{eq} = E + E + E + E = 4E\] \[R_{eq} = r' + r' + r' + r' Show more…
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