Question
Figure shows four cell $\mathrm{E}, \mathrm{F}, \mathrm{G}$ and $\mathrm{H}$ of emfs $2 \mathrm{~V}, 1 \mathrm{~V}, 3 \mathrm{~V}$ and $1 \mathrm{~V}$ and internal resistances $2 \Omega, 1 \Omega, 3 \Omega$ and $1 \Omega$ respectively
Step 1
The cells E, F, G, and H are connected in a rectangular shape with their emfs and internal resistances. A resistance of 2 ohms is connected diagonally across the circuit. Show more…
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Figure shows four cell $E, F, G$ and $H$ of emfs $2 V, 1 V, 3 V$ and $1 \mathrm{~V}$ and internal resistances $2 \Omega, 1 \Omega, 3 \Omega$ and $1 \Omega$ respectively
Figure shows four cell $\mathrm{E}, \mathrm{F}, \mathrm{G}$ and $\mathrm{H}$ of emfs $2 \mathrm{~V}, 1 \mathrm{~V}, 3 \mathrm{~V}$ and $1 \mathrm{~V}$ and internal resistances $2 \Omega, 1 \Omega, 3 \Omega$ and $1 \Omega$ respectivelyThe current flowing in the $2 \Omega$ resistor is. $($ A $)(1 / 7) A$ (B) $(1 / 9) \mathrm{A}$ (C) $(1 / 11) \mathrm{A}$ (D) $(1 / 13) \mathrm{A}$
Two cells having emf $4 \mathrm{~V}$ and $2 \mathrm{~V}$ and internal resistance $1 \Omega$ and $1 \Omega$ are connected as shown in the figure. Current through $6 \Omega$ resistance is (a) $(1 / 3) \mathrm{A}$ (b) $(2 / 3) \mathrm{A}$ (c) $(2 / 6) \mathrm{A}$ (d) $(2 / 9) \mathrm{A}$
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