00:01
Okay, so for this question, we are going to fill in the chart, and i've rewritten it out how it's given in the textbook.
00:05
So started with the first one, we have co2, which has essential carbon with two oxygens, double bonded.
00:13
This has an electron domain geometry that is linear, since there's two regions of electron density, and the hybridization of the carbon is sp hybridized.
00:25
And since this is a symmetrical molecule, the dipoles cancel out, so there is no dipole moment.
00:33
For a molecule with an sp3 hybridization, and we know that its electron geometry must be tetrahedral, since there's four regions of electron density.
00:47
In this case, there is a dipole.
00:48
So an example of this would be nh3, since it has a lone pair and three hydrogen bonds.
00:57
So this counts as four regions of electron density.
01:00
One of them is a lump of electron, so that makes it have a dipole moment.
01:07
Next we have another example of sp3.
01:10
So again, it will be tetrahedral, but there's no dipole moment.
01:14
So this can be ch4, since it's just four hydrogens on the central carbon, no dipole moments.
01:28
Next, we have trigonal planar shape that has no dipole moment.
01:35
Since it's trigonal planar, we know that it has three regions of electron density, so it must be sp2 hybridized.
01:40
An example of this is bf3, has a central boron bonded to three fluorines.
01:50
Next, sf4 will have four bonds to four fluorines and a lone pair of electrons...