00:01
We are given here the balanced chemical equation of the reaction between silver bromide and sodium thysulfate, which produces sodium -silver thiosulfate and sodium bromide.
00:44
Okay? we need to determine the mass of sodium silver thiosulfate that is produced if what we have, if we start with 0 .275 grams of silver bromide.
01:07
Because silver bromide and sodium silver thiosulfate are the substances involved in this question.
01:16
We are going to establish the mole ratio between these two substances so one mole of silver bromide react to produce one mole of sodium silver thiosulfate and we want to write this ratio here to make the calculations one mole of silver bromide to one more of sodium silver thyosulfate because we are given grams and we need to give the answering grams we have to convert the moles into grams by calculating by multiplying by the molar mass of each of this compound so for silver bromide the atomic weight of silver is 107 .87 plus the atomic weight of broming which is 179000 in the case of sodium silver thyosulfate, we multiply by 3 times 23.
02:52
So three sodium times 23, the atomic weight of sodium plus 107 .87, the atomic weight of silver, plus plus four times, two times sulfur, atomic weight of sulfur is 32.
03:11
Plus 6 times 16, the atomic weight of oxygen.
03:25
Grams per mole, grams per mole.
03:31
Moles will cancel...