00:01
In this problem, we are constructing four by four matrices to satisfy some sort of condition that we're given.
00:09
And we have to do this three different times.
00:12
So what we need to pay attention in this problem is the indices that we're given.
00:17
So for example, in this first part a, we define a matrix sub ij, where i and j are the number of our rows and columns.
00:26
So that's just something that we need to keep track of because that's going to tell us.
00:31
Essentially how to construct these matrices.
00:35
So for part a, we're told that a sub ij is equal to i plus j.
00:41
So what does that look like in our matrices? and i will read them going down a column.
00:47
So this first column will have 1 plus 1.
00:50
So this is essentially our first column plus our first row or vice versa.
00:57
So down this column we'd have 1 plus 1, 2 plus 1, 3 plus 1, 3 plus 3.
01:01
1, 4 plus 1, where this first number is the number of our row and the second number is the number of our column.
01:09
And then we have this pattern continue.
01:11
So our second column would be 1 plus 2, 2 plus 2, 3 plus 2, 4 plus 2, where when we add 2 each time, that's the number of our column.
01:21
So this repeats until we get up to 4 columns.
01:25
And we'll find that our final 4x, when i'm going to read this again by column, would be 2.
01:31
Two, three, four, five, five, six, four, five, six, seven, five, six, seven, eight.
01:39
And that is our four by four matrix.
01:46
Now, for part b, i think i wrote this a little bit incorrectly.
01:50
I think i rewrote a, but part b, i believe, was a sub ij raised to ij...