Problem

Find a unit vector that has the same direction as…

02:30

Problem 22 Easy Difficulty

Find $ a + b , 4a + 2b , \mid a \mid $, and $ \mid a - b \mid $.

$ a = \langle 8, 1, -4 \rangle , b = \langle 5, -2, 1 \rangle $

Answer

$$
|\mathbf{a}-\mathbf{b}|=\sqrt{3^{2}+3^{2}+(-5)^{2}}=\sqrt{9+9+25}=\sqrt{43}
$$

Discussion

You must be signed in to discuss.

Knowledge S.

February 2, 2021

Is it me going nuts or does 9+9+25=45? Sgould not it equal 43?

Top Calculus 3 Educators

Watch More Solved Questions in Chapter 12

Problem 1

Problem 2

Problem 3

Problem 4

Problem 5

Problem 6

Problem 7

Problem 8

Problem 9

Problem 10

Problem 11

Problem 12

Problem 13

Problem 14

Problem 15

Problem 16

Problem 17

Problem 18

Problem 19

Problem 20

Problem 21

Problem 22

Problem 23

Problem 24

Problem 25

Problem 26

Problem 27

Problem 28

Problem 29

Problem 30

Problem 31

Problem 32

Problem 33

Problem 34

Problem 35

Problem 36

Problem 37

Problem 38

Problem 39

Problem 40

Problem 41

Problem 42

Problem 43

Problem 44

Problem 45

Problem 46

Problem 47

Problem 48

Problem 49

Problem 50

Problem 51

Problem 52

Video Transcript

for the given problem, we want to evaluate to some of the factors knowing that vector A is going to be 8 1 -4 And the B vector is going to be 5 -2, 1 with some of these vectors. If we do A plus B, okay, is going to be the component added together. So eight plus 5 13, 1 minus two, negative one and negative four plus one negative three. Then we want to find the magnitude of a. So magnitude of A is going to be the square root of eight squared, which is 64 Plus one Squared, which is one Um plus a negative 4th grade, which is 16. That takes us to 81 squared of 81 we know is nine. So that's the magnitude and this is the final answer.

Carson M.

California Baptist University

Topics

Vectors

Calculus: Early Transcendentals

Chapter 12

Vectors and the Geometry of Space

Section 2

Vectors

Problem

Find a unit vector that has the same direction as…

Problem 22 Easy Difficulty

Find $ a + b , 4a + 2b , \mid a \mid $, and $ \mid a - b \mid $.

$ a = \langle 8, 1, -4 \rangle , b = \langle 5, -2, 1 \rangle $

Answer

$$
|\mathbf{a}-\mathbf{b}|=\sqrt{3^{2}+3^{2}+(-5)^{2}}=\sqrt{9+9+25}=\sqrt{43}
$$

More Answers

Topics

Calculus: Early Transcendentals

Discussion

Top Calculus 3 Educators

Lily A.

Catherine R.

Kayleah T.

Samuel H.

Calculus 3 Bootcamp

Vectors Intro

Vector Basics - Example 1

Recommended Videos

Watch More Solved Questions in Chapter 12

Video Transcript

Topics

Calculus: Early Transcendentals

Top Calculus 3 Educators

Lily A.

Catherine R.

Kayleah T.

Samuel H.

Calculus 3 Bootcamp

Vectors Intro

Vector Basics - Example 1

Recommended Videos

Problem

Find a unit vector that has the same direction as…

Problem 22 Easy Difficulty

Find $ a + b , 4a + 2b , \mid a \mid $, and $ \mid a - b \mid $. $ a = \langle 8, 1, -4 \rangle , b = \langle 5, -2, 1 \rangle $

Answer

$$|\mathbf{a}-\mathbf{b}|=\sqrt{3^{2}+3^{2}+(-5)^{2}}=\sqrt{9+9+25}=\sqrt{43}$$

More Answers

Topics

Calculus: Early Transcendentals

Discussion

Top Calculus 3 Educators

Lily A.

Catherine R.

Kayleah T.

Samuel H.

Calculus 3 Bootcamp

Vectors Intro

Vector Basics - Example 1

Recommended Videos

Watch More Solved Questions in Chapter 12

Video Transcript

Topics

Calculus: Early Transcendentals

Top Calculus 3 Educators

Lily A.

Catherine R.

Kayleah T.

Samuel H.

Calculus 3 Bootcamp

Vectors Intro

Vector Basics - Example 1

Recommended Videos

Find $ a + b , 4a + 2b , \mid a \mid $, and $ \mid a - b \mid $.

$ a = \langle 8, 1, -4 \rangle , b = \langle 5, -2, 1 \rangle $

$$
|\mathbf{a}-\mathbf{b}|=\sqrt{3^{2}+3^{2}+(-5)^{2}}=\sqrt{9+9+25}=\sqrt{43}
$$