To do this, we can set two of the variables equal to 1 and solve for the third.
If we set $y=1$ and $z=0$, we get $x=2$. So one basis vector is $(2,1,0)$.
If we set $x=0$ and $z=1$, we get $y=-1$. So another basis vector is $(0,-1,1)$.
So, the basis for the
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