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Numerade Educator



Problem 2 Easy Difficulty

Find $ a \cdot b $.

$ a = \langle 5, -2 \rangle $ , $ b = \langle 3, 4 \rangle $



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Video Transcript

in this problem, we are given two vectors A and B, and we're told that we need to multiply our two vectors. We have to find a times B, and that's what we're going to be doing. So eight times we would be equal to our first factor. Five common negative two times or second vector three, comma four. So how would we multiply these vectors? This would be equal to five times three minus two times four. So that simplifies to 15 minus eight. And we find that the product of these two vectors is seven. So I hope that this problem helped you understand a little bit more about how we could multiply two vectors and the process that we go through to find that value.