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Numerade Educator

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Problem 4 Easy Difficulty

Find $ a \cdot b $.

$ a = \langle 6, -2, 3 \rangle $ , $ b = \langle 2, 5, -1 \rangle $

Answer

$a \cdot b=-1$

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Video Transcript

Okay, So to find the dot product here, we just multiply component wise and at twelve minus ten minus three, it's negative one.