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Numerade Educator

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Problem 6 Easy Difficulty

Find $ a \cdot b $.

$ a = \langle p, -p, 2p \rangle $ , $ b = \langle 2q, q, -q \rangle $

Answer

$-p q$

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Video Transcript

okay to find the doc product here we multiply component wise and at the moment. Okay, so this one's with variables, but it's totally fine.