00:02
So for this problem, we're given three universally quantified statements, and we want to see if we can find a counter example to each of these.
00:09
So keep in mind that each of these x and y values are going to be integers.
00:15
So let's start by looking at part a.
00:18
So this statement says that for every x, there exists a y such that x is equal to 1 over y.
00:25
So we can take any value of x, any integer, and it's saying that we can set it equal to 1 divided by some number.
00:32
We can find that number.
00:33
Now the thing that we would have to think about is, can we just fit any old number in for y? can we always find this value for y? and the tricky thing here is that it has a fraction.
00:49
So we have 1 divided by y.
00:51
Y is an integer.
00:53
Is there any integer that we can't divide by? like, is there any number that we could plug in for y that would just render this whole thing useless, that we just would completely mess it up? so remember that we can't divide by 0.
01:09
Right? 1 divided by 0 doesn't make any sense.
01:12
So if we set y to be equal to 0, then we couldn't really find an x.
01:17
There would be no value x that's equal to 1 over 0, because 1 over 0 isn't defined.
01:24
So our counter example here is, say, y equals 0.
01:29
Because there is no value x that's equal to 1 divided by 0.
01:33
For part b, this statement is saying that for every x, there exists a y such that y squared minus x is less than 100.
01:47
So this one, again, we're saying for every x, so any value that we plug in x, we can find a particular value for y such that this is true.
01:57
The thing to keep in mind here is that y squared is always going to be a positive number.
02:05
If we square a number, we can't get an output that's negative.
02:11
So just kind of as a note, y squared is always going to be greater than or equal to 0...