Question
finda. $(f \circ g)(x)$b. $\quad(g \circ f)(x)$c. $(f \circ g)(2)$$f(x)=2 x-3, \quad g(x)=\frac{x+3}{2}$
Step 1
This means we substitute $g(x)$ into the function $f(x)$. So, we have $f(g(x)) = f\left(\frac{x+3}{2}\right)$. Show more…
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