Question
Find a formula for each of the sums and then use these formulas to calculate each sum for $n=100$, $n=500,$ and $n=1000 .$$$\sum_{k=1}^{n} \frac{k^{3}-1}{4}$$
Step 1
Step 1: First, we separate the sum into two parts: $$ \sum_{k=1}^{n} \frac{k^{3}-1}{4} = \frac{1}{4} \sum_{k=1}^{n} k^{3} - \frac{1}{4} \sum_{k=1}^{n} 1 $$ Show more…
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