00:01
All right, we have this parabola here, and it's only defined for x greater than equal to 1, because its domain has to be restricted.
00:12
So this is the domain.
00:14
And remember, domain means what x values you can put into the function.
00:20
Okay, so we need to have a look at this parabola so we can make sure that it's one -to -one so that it actually does have an inverse.
00:28
And because i'm going to need it later, i'm going to go ahead and figure out where it is by completing the square.
00:35
So i'm going to add something and i'm going to subtract something.
00:38
So i'm going to add half of minus two squared.
00:45
So half of minus two is minus one and minus one squared is one.
00:49
Oops.
00:50
So i'm going to add one and at the same time i'm going to subtract one.
00:54
Okay.
00:55
So i haven't changed the equation.
00:57
It's still x squared minus 2x.
00:59
But now i can write it in this form.
01:01
This is a perfect square.
01:02
That's why it's called completing the square.
01:04
It's x minus 1 squared minus 1.
01:08
Okay, now i can see that the vertex of this parabola is 1 minus 1.
01:16
Okay, because when it's in this form, x minus h squared plus k, then hk is the vertex.
01:27
Okay, so there's a minus here.
01:29
That means h is 1, but there's a minus here.
01:32
That means k is minus 1.
01:35
All right.
01:36
So we have a vertex at 1, 1.
01:41
And if we would have just factored this in the first place, it's x times x minus 2, we have x intercepts at 0 and 2.
01:49
Okay, so now we have a pretty clear picture of what the parabola looks like.
01:56
Oh, it's most beautiful parabola.
01:59
Okay, but now we have to restrict it, only use the parabola for the part of the graph where x is greater than or equal to 1.
02:09
So here's one.
02:10
So, here's one.
02:10
We're going to keep this half over here, and we're going to get rid of the rest of it.
02:19
Okay, so we also need to know what is the range of this function...