Question
Find a formula for the $n$ th term of each sequence.$$\text { (a) } \frac{1}{1}, \frac{-1}{8}, \frac{1}{27}, \ldots \quad \text { (b) } \frac{2}{6}, \frac{3}{7}, \frac{4}{8}, \ldots$$
Step 1
For sequence (a), we can see that the numerator alternates between positive and negative, starting with positive. This can be represented by $(-1)^{n+1}$. The denominator is the cube of the term number, which can be represented by $n^3$. For sequence (b), the Show more…
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