Question
Find a formula for the $n$th term of the sequence.$$\frac{1}{25}, \frac{8}{125}, \frac{27}{625}, \frac{64}{3125}, \frac{125}{15,625}, \dots$$
Step 1
We see that they are 1, 8, 27, 64, 125, which are the cubes of the natural numbers. So, the numerator of the nth term is $n^{3}$. Show more…
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Determine the explicit formula for the n^th term of the sequence written below: 25, 125/8, 625/27, 3125/64, 125, 78125/216, ... Provide your answer below:
Find a formula for the $n$ th term of the sequence. $$-\frac{1}{25}, \frac{8}{125}, \frac{27}{625}, \frac{64}{3125}, \frac{125}{15,625}, \ldots \quad \begin{array}{l} \text { Cubes of positive integers } \\ \text { divided by powers of } 5 \end{array}$$
Infinite Sequences and Series
Sequences
Write an explicit formula for the nth term of the sequence.
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