Question
Find a formula for the $n$th term of the sequence.$$\sin \left(\frac{\sqrt{2}}{1+4}\right), \sin \left(\frac{\sqrt{3}}{1+9}\right), \sin \left(\frac{\sqrt{4}}{1+16}\right), \sin \left(\frac{\sqrt{5}}{1+25}\right), \dots$$
Step 1
We can see that the terms of the sequence are of the form $\sin \left(\frac{\sqrt{n}}{1+n^2}\right)$, where $n$ is the number under the square root and also the number being squared in the denominator. Show more…
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