Question
Find a parametrization of the tangent line at the point indicated.$$\mathbf{r}(s)=(\ln s) \mathbf{i}+s^{-1} \mathbf{j}+9 s \mathbf{k}, \quad s=1$$
Step 1
The derivative of a vector function is found by taking the derivative of each of its component functions. So, we have: $$ \mathbf{r}'(s)=\frac{d}{ds}(\ln s) \mathbf{i}+\frac{d}{ds}(s^{-1}) \mathbf{j}+\frac{d}{ds}(9s) \mathbf{k} $$ Show more…
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