Question
Find a plane through the points $P_{1}(1,2,3), P_{2}(3,2,1)$ and perpendicular to the plane $4 x-y+2 z=7$
Step 1
We can use the two given points $P_1(1,2,3)$ and $P_2(3,2,1)$ to find this vector. The vector $\vec{v_1}$ is given by $P_2 - P_1$, which is $(3-1, 2-2, 1-3) = (2, 0, -2)$. Show more…
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Find a plane through the points P1(1, 2, 3), P2(3, 2, 1) and perpendicular to the plane 4x - y + 2z = 7.
Find a plane through the points P1(1, 2, 3), P2(3, 2, 1), and perpendicular to the plane 4x - y + 2z = 7.
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