00:01
Here in this question a sequence is given to us which is 1 ,7, 13, 19, 25 and so on.
00:13
And we have to find out a plausible formula for the journal term of the given sequence.
00:22
That is, we have to find out ak.
00:26
So firstly, we need to check the type of the given sequence.
00:31
This we need to check the difference of next term with the previous term.
00:38
Say here a1 is equal to 1, a2 is equal to 7, a3 is equal to 13, a4 is equal to 19 and so on.
00:52
So we need to check the difference of next term with previous one, that is a2 minus a1.
01:00
So here a2 minus 7.
01:00
So here a2 minus 7 is 7 minus 1 that is 6 because only by checking one term it's not sure that the sequence is of arithmetic time.
01:13
So we need to check more...