00:01
We have the orthogonal basis p0, p1, p2, given by the polynomials 1, t, and t squared minus 2.
00:09
We know this from example 5.
00:11
So let me write p0 bar for the vector obtained by computing p0 in minus 2, in minus 1, in 0, in 1, and in 2.
00:23
So this is just the vector of 1s.
00:26
And then p1 bar is minus 2, minus 1, 0 and 2.
00:30
And finally p2 bar is 2 minus 1 minus 2 minus 1 and 2 now we write these vectors because we are called the inner product between polynomials so in this case for instance p 0 against b 0 is given by p 0 bar dot p 0 bar so in this case is 5 and similarly we compute p 1 against p 1 to be 10 and p2 against b2 to be 14 we compute these numbers now because we are going to use them now, well soon, when we are doing the grand schmitt process.
01:07
So let's consider the polynomial q, which is given by t cubed.
01:12
Let's write q bar.
01:13
Of course, this is minus 8, minus 1, 0, 1 and 8.
01:17
And we want to apply the grans schmidt process to q to obtain, well, to obtain a vector which is orthogonal to both p0, p1 and p2.
01:28
So now the computation is simplified by the fact that the vectors p0, p1 and p2 are, well, the vectors, the polynomials, p0, p1, p2 are already orthogonal.
01:40
So all we need to do is to compute the projection of q onto p0, p1 and p2.
01:49
So let's start with p0, which is q against p0, divided by p0 against p0.
01:55
And of course we recall that this is q bar dot p0 bar divided by 5 the 5 we computed previously and then p 0 is just the constant function 1 and now you can compute a q bar dot p0 bar is 0...