00:01
So what we have here are cities, we're going to label them.
00:04
So this will be a, this will be b, this will be c.
00:11
Then we'll have d and e, and a connects d.
00:20
We also have that e connects to b and c.
00:24
We have that d connects to all of these, and then a connects to all of them.
00:35
And c connects to all of them as well so all these are connected to each other but we do have different weights we have 119 429 409 389 379 319 309 239 229 109 so based on this we want to determine what would be the best route for us to take.
01:22
And we end up, we could do a bunch of different possibilities, but we would have to write out every single one.
01:33
So for example, we could do from a to b to c to d to d to e back to a.
01:46
But then that would cost 11.
01:50
Or we could do other ones and we would keep going throughout this process.
01:55
But what we end up seeing is the way to make it cheapest is for us to somehow use the 109 and the 119.
02:03
That's how we're going to make it cheapest.
02:05
We want to figure out what are the cheapest values.
02:09
We have the 109, the 119, the 239...