00:01
Okay, so it's asking us to find a so that our two vectors have the same magnitude.
00:09
Well, notice, whether they're positive or negative, they really have the same values in i, j, and k, right? they both have a 2, or a 2a in the i component.
00:19
Both the js are 1s and both the ks are ones.
00:22
You know, one's negative 1, but when you square it, that's not going to matter.
00:26
So it looks like a is 1, but let's do that more formally.
00:30
Let's actually put the two magnitudes equal to each other.
00:34
So we have like a two square plus a one squared plus negative one squared.
00:40
And you take the square root and that has to equal our 2a squared plus our 1 squared plus our 1 squared...