00:01
So the way we find the basis of the span of the set of vectors that given here, v1 through v5, is to put the vectors into a matrix and then find the column space of the matrix.
00:11
So we have the vectors here to find the column space we start doing gauzing elimination.
00:16
So we copy over our first row, and then we're going to add the first two rows together to get our new second row.
00:28
So we get a 0, 1, a negative 1, a 4, and an 11.
00:34
Then we're going to multiply our first row by negative.
00:37
5 and added to our third row.
00:39
So that's going to be a 0.
00:41
Negative 2 times negative 5 is 10.
00:42
So this is going to be an 11.
00:44
Negative 4 times negative 5 is negative 20 plus 9 is negative 11.
00:51
Then we just have a 2 here.
00:53
Then we have negative 7 times negative 5, which is going to be 35 plus 2 is just 37.
01:03
And then we'll multiply our top row by negative 2 and add it to the last row.
01:07
So we get a 0.
01:08
We get a positive 4 here.
01:11
We get a negative 4 here, a negative 3 here.
01:15
And then we get negative 7 times negative 2, which is positive 14, minus 8, which is going to be just a 6.
01:23
All right, so let's go ahead and copy that over to the left.
01:28
And then we'll try to zero out the second column.
01:30
We'll do that by multiplying the second row by 2 and adding it to the first.
01:34
So that gives us a 1, a 0, a 2, a 2, and 8...