00:01
In this problem, we have a 2 kilogram copper block, which is taken from 25 degrees celsius to 100 degrees celsius.
00:07
The specific heat of copper is given, and we want to find out two quantities.
00:12
For the first thing, it's heat.
00:15
Now, the definition of specific heat is that the amount of heat required to change the temperature by dt is equal to cmdt.
00:28
That is, to change the temperature of a copper block of mass m by d t is simply cmd.
00:37
Now by integrating this on both sides, we'll see that on the left -hand side q is equal to, because cm and cm are usually both constants, in this, the specific heat is usually a constant over our temperature range, we can simply pull them out of integration and integrate over t giving us cm delta t this is the usual definition we have so we'll simply use this heat is simply 386 jule per kg kelvin remember that one degree change in celsius is the same as one degree change in kelvin so the units are both the same mass is two kilograms and the change in temperature is 75 kelvin 100 degrees minus 25 degrees is 75 degrees celsius which is the same as 75 kelvin change in temperature.
01:26
So that is it.
01:28
The cages cancel, the kelvin's cancel, and the number turns out to be 5 .79 times 10 power 4 jules...