Question
Find (a) the mean and (b) the median of the random variable with the given pdf.$$f(x)=4 x^{3}, 0 \leq x \leq 1$$
Step 1
In this case, the range of X is from 0 to 1. So, we have: $$\mu = \int_{0}^{1} x*f(x) dx = \int_{0}^{1} x*4x^{3} dx = \int_{0}^{1} 4x^{4} dx$$ Show more…
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Find (a) the mean and (b) the median of the random variable with the given pdf. $$ f(x)=4 x^{3},[0,1] $$
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