We can convert this energy to joules by multiplying by the charge of an electron ($1.6 \times 10^{-19} \, \text{C}$), since $1 \, \text{eV} = 1.6 \times 10^{-19} \, \text{J}$. Therefore, the energy of the proton in joules is $7 \times 10^{12} \, \text{eV} \times
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