00:01
We are going to find the unit vector normal to the plane containing vnw.
00:06
So in order to do that, we need to first do the cross product of vnw.
00:12
So to do that, we're going to write our ijk out, and we're first going to put our vector v.
00:18
So we got a 2 -6, negative 3, and then w is 4, 3, negative 1.
00:24
Okay, so let's start with our i component.
00:28
It.
00:29
So we're going to be taking a negative 6 times negative 1 minus a 3 times negative 3.
00:38
Now we always say minus for our j direction and we're going to have that 2 times negative 1 minus a 4 times negative 3.
00:48
I mean negative 12, sorry.
00:52
Oh yeah, 4 times negative 3 is going to be minus a negative 12.
00:56
Okay, now for our k, we'll have our two times three minus our four times negative six.
01:04
Okay, so if we clean these up, we have a 15 in the i direction, a negative 10 in the j direction, and then a 30 in the k direction.
01:16
Okay, so this gives us our cross product...