Question

Find a vector function that represents the curve of intersection of the two surfaces. The paraboloid $z=4 x^2+y^2$ and the parabolic cylinder $y=x^2$

    Find a vector function that represents the curve of intersection of the two surfaces.
The paraboloid $z=4 x^2+y^2$ and the parabolic cylinder $y=x^2$
Single Variable Calculus: Early Transcendentals
Single Variable Calculus: Early Transcendentals
James Stewart,… 9th Edition
Chapter 13, Problem 52 ↓
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Find a vector function that represents the curve of intersection of the two surfaces. The paraboloid $z=4 x^2+y^2$ and the parabolic cylinder $y=x^2$
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Find a vector function that represents the curve of intersection of the two surfaces. The paraboloid $ z = 4x^2 + y^2 $ and the parabolic cylinder $ y = x^2 $

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00:01 In this question, we want to find a vector function that represents the curve of intersection of the two surfaces.
00:08 Here we have the paraboloid z equals 4x squared plus y squared and the parabolic cylinder y equals x squared.
00:19 So we're going to deal with the easier one first.
00:22 We're going to start with y equals x squared.
00:25 And we're going to have to introduce a parameter t.
00:30 So specifically, i am going to let x equal t.
00:35 If x is equal to t, then y, since that was equal to x squared, my y is equal to t squared.
00:45 Now, i need to figure out what z is in terms of t as well.
00:50 But remember, z was equal to 4x squared plus y squared.
00:56 So we're going to do a substitution.
00:58 I'm going to replace my x with t and my y with t squared...
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