00:01
In order to find a critical point for a function in two variables, i first need to find the partial derivative with respect to each variable.
00:09
So if i have a function in x and y of x cubed over 3 minus y cubed over 3 plus 3xy, first i will find the partial derivative with respect to x, and that gives me x squared plus 3y.
00:28
Then i can find the partial derivative with respect to y.
00:33
That is negative y squared plus 3x.
00:39
So my critical points will occur when either one of these partial derivatives does not exist, which doesn't happen in this case, or when both partial derivatives are equal to zero.
00:51
So i'm going to start by taking this equation and setting it equal to zero.
00:58
And i'm going to solve for x.
01:03
Now i have that value of x.
01:05
I'm going to plug it into the second equation, this one right here.
01:11
So if i do that, that gives me x squared plus 3y equals 0.
01:21
X is y squared over 3 squared.
01:27
And i'm going to simplify this a little bit.
01:29
Y to the fourth over 9 plus 3y equals 0.
01:36
I'm going to simplify a little...