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Find all integer values of $b$ that make $2 x^{2}+b x-5$ factorable.

$b=-9(or)-3(or) 3(or) 9$

Algebra

Chapter 6

Factoring and Quadratic Equations

Section 3

Factoring Trinomials of the Form $a x^{2}+b x+c 454$

Equations and Inequalities

Quadratic Functions

Campbell University

Oregon State University

Baylor University

University of Michigan - Ann Arbor

Lectures

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Find all integers b so tha…

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Find all integers, $b$, th…

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01:31

03:52

Find all positive values o…

Okay, so we have to find audit and to do values will be such that this falling polynomial is factory Izabal. So let's see. So we see that we can rewrite it as a binomial with X and fronts. And since two of the prime number, you know, that's a term in front of exes eater or is just two and one and in the same boat for five, since it's a prime number are ending. Term is he is both five and one, so we can write it like five and one here, or we can rewrite it as two x one and one x fine. And if you notice are signs, we have a negative sign here and a positive sign here. And so that means that, um, we're gonna have opposite signs for our binomial. But are, um please, but our larger number needs to be positive. Let's see, Let's see, you've used to work, So I'm gonna make this positive and negative and see if this factory station works almost white out. We get to X squared minus two x plus five X and then minus five. We yet two x squared minus or a plus. three X and then minus five. And then we can. This seems to refine so we can have a B that's equal to three. So if you have a positive and negative here, what we get, we get to X squared minus 10 X plus X and in mind, it's fine. Okay, so that gives me a to X squared minus nine X minus five so we can have a B that's equal to negative nine. Since we're only since we're asking for interviews are be about. You should also be negative, and we can also swap or signs. So we get to X minus five and two her X Plus one as well as two x minus one times X plus five. So let's see what we get. We get two x squared plus two x minus five x and then minus five, so our be value is negative. Three x negative three and then for this one, get to X squared plus 10 x minus X minus five. Between this, a B value of nine so RV values are equal to three negative three nine and negative nine

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