00:01
For problem number three, we are asked to find all x values that have to be excluded from our domain.
00:06
So in this case, we have x plus 5 over x squared minus 25.
00:14
Now, in this specific case, we do have two expressions, top and bottom, but all we care about again is our denominator.
00:23
Our denominator cannot equal zero.
00:25
So we do not care about x plus 5.
00:27
We don't use that for anything.
00:28
To answer this question, we're just going to take x squared, minus 1.
00:31
25 and set that equal to 0.
00:35
Now you should say that we have a difference of two squares...