Substituting this into the second equation, we get $y - (y^2)^2 = 0$. Simplifying, we have $y - y^4 = 0$. Factoring out $y$, we get $y(1 - y^3) = 0$.
So either $y = 0$ or $1 - y^3 = 0$. If $y = 0$, then substituting back into the first equation, we get $x = 0$.
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