00:01
Hello and welcome to this video where we're going to find the solutions for this trigonetric equation between all the solutions are between zero and two pi so before we even get into it we need to be familiar with a couple of things one we need to be familiar with the unit circle and sort of all the pieces of it and more specifically we need to be aware of what's happening in the first quadrant of the unit circle and what are the x and y points associated with the different radiance? so for example if we're looking at at pi over six, we need to know that that corresponds to root 3 over 2, one half.
00:37
The next one is pi over 4, and that this is going to be root 2 over 2, comma root 2 over 2.
00:45
And then finally, pi over 3, and that corresponds to points 1 1⁄2, root 3 over 2.
00:57
There we go.
00:58
So we have to have to our back pocket.
01:01
When we have that in our back pocket, then these problems are going to be a piece of cake.
01:05
So first thing we want to do is get our trig function all by itself.
01:08
So we're going to divide both sides by two.
01:11
As a result, we're looking at sine of theta is equal to negative 1 half.
01:15
Well, here's what we're going to do.
01:17
Sign is associated with the y coordinate...