Question
Find an equation for the line tangent to the curve at the point defined by the given value of $t .$ Also, find the value of $d^{2} v / d x^{2}$ at this point.$$x=2 t^{2}+3, \quad y=t^{4}, \quad t=-1$$
Step 1
We have $x=2t^2+3$ and $y=t^4$. The derivative of $x$ with respect to $t$ is $dx/dt = 4t$ and the derivative of $y$ with respect to $t$ is $dy/dt = 4t^3$. Show more…
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