00:01
As the equation say that find an equation for the plane containing the point 2, 3, 4.
00:07
Let us say this point is l and the line x equal to 1 plus 2t, y equal to 3 minus t and z equal to 4 plus t.
00:21
So let us first find out the cartesian equation of the line.
00:25
This is parametric equation.
00:26
So from here t will be x minus 1 by 2 and t will be 3 minus y and from here t will be z minus 4.
00:42
If we equate all the values of t it will be x minus 1 by 2, 3 minus y, z minus 4.
00:52
This could be written as x minus 1 by 2 and i will be dividing with minus 1, y minus 3 and z minus 4 by 1.
01:02
I have to compare this with x minus x1 by a, a1 let us say and y minus y1 by b and z minus z1 by c.
01:19
Let us say i will write this only, a, b and c.
01:24
So the point on the line or the line passes through minus 1, minus 3, minus 4.
01:32
Let us write point a and this is point p, not l.
01:38
And this point a and this point p, that is these two points will lie on the plane.
01:44
Now i will be finding out the equation of the normal to the plane because we have equation of, required equation of plane that will be a into x minus x1 plus b into y minus y1 plus c into z minus z1 equal to 0 where a, b, c are the direction cosines of the normal perpendicular to the plane or normal to the plane.
02:21
Both are one and the same thing...