00:01
In this problem, we're asked to find the tangent line to the curve y equals x minus 1 squared plus 1 at the point 1 comma 1, and then to sketch the curve and the tangent line.
00:12
So to find the tangent line, we need to find the slope of the tangent line.
00:16
So the slope of the graph, slope of graph, at x equals 1.
00:24
So this is the x coordinate here.
00:28
So this is the limit expression from the section.
00:31
This is the limit as h approaches 0 of 1 plus h minus 1 squared plus 1.
00:41
That's our first term.
00:44
And then minus 1 minus 1 squared plus 1, all divided by h.
00:53
So where did this come from? so this x equals 1, that's coming right here and right here.
01:02
And so this part of the expression, this is the like x plus h part of the expression.
01:08
That's where this is one plus h is coming from.
01:10
Here's the x plus h.
01:11
Here's the x.
01:12
And we're plugging in x equals one.
01:16
So now we can evaluate this limit.
01:17
So we should try and simplify some things a little bit.
01:20
This is the limit as h approach is zero of.
01:23
Well, let's simplify.
01:25
1 plus h minus 1 is h.
01:28
So h squared plus 1 minus...