00:02
So for this question, our goal is to find the equation of the plane with the given three points.
00:08
So to do that, we're going to need to find first two vectors in the plane.
00:13
And for simplicity, let's call this a, b, and c.
00:22
Let's call the two vectors that we're looking for v1 and v2.
00:32
And you can find vectors by subtracting the coordinates for the point.
00:37
To do b minus a and c minus a.
00:43
Okay.
00:46
So this will give us two vectors in the plane.
00:49
So we're going to subtract component -wise.
00:51
You should get x2 minus x1, negative y1, and then positive z2.
01:07
For c -minus a, we will get negative x1, y3 minus y -1, and then positive z3.
01:20
Okay, now what we need is the normal vector.
01:25
And the normal vector for a plane is calculated by taking the cross product of any two vectors in the plane.
01:33
So we can take our v1 crossed v2 and get a new vector.
01:41
So let's see what that comes out to.
01:44
For the x component, we should get negative y1 z3 minus minus z2 times y3 minus y1.
02:06
Okay, so there's our x component.
02:10
Then we should have negative x1 z2 minus z3 times x2 minus x1...