Question
Find an equation of the line of intersection of the two given planes.$$x=4 \text { and } 3 x-5 y+2 z=-3$$
Step 1
The normal vector to the plane $x=4$ is $\langle 1,0,0 \rangle$. The normal vector to the second plane $3x-5y+2z=-3$ is $\langle 3,-5,2 \rangle$. Show more…
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