00:01
All right, so for problem 92, we need to create a perpendicular bisector to a line segment that goes through the points negative 6, negative 3, and negative 8, negative 1.
00:14
And so a horizontal bisector is ultimately going to be an equation in the form of y equals mx plus b, and it is going to have the inverse slope of this line segment.
00:25
So let's start by getting the slope of this line segment.
00:27
So m equals rise over run or negative 1 minus negative 3 divided by run.
00:35
So negative 8 minus negative 6.
00:38
And what does that come out to? well, negative 1 plus 3 is going to be 2.
00:43
And then negative 8 plus 6 is going to be negative 2.
00:46
So negative 1 is going to be our slope.
00:49
However, we actually need to invert this as it's going to be perpendicular.
00:53
So our actual slope is going to flip this...
