00:01
So for this exercise, we're given the points p with these coordinates, q with the coordinates 1, 2, 1, 2, 3, and r with coordinates 4, 7, 7, 6.
00:14
And we want to find an equation for a plane that passes through these points.
00:20
So to do that, we need to find a normal vector for that plane, and to do that, we will calculate the cross -product of two vectors that we can.
00:30
Create using these points.
00:33
Let's first look at the vector qp.
00:38
This is, you could choose any two vectors, but qp seems like it will be easy to calculate.
00:44
So we have three minus one, four minus two, five minus three, which is equal to two, two, two.
00:55
And then let's also calculate qr, again, because we will only get positive numbers and it will be easier for calculations and we have 4 minus 1 7 minus 2 6 minus 3 we have 3 5 3 so now we need to calculate the cross product of these 2 so q p cross q r is equal to the determinant we put ijk on top, then we have 2 -2 -2 for qp and 353 for qr.
01:38
And now we need to calculate recursively using the formula for the determinant...