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Numerade Educator



Problem 23 Easy Difficulty

Find an equation of the plane.

The plane through the origin and perpendicular to the vector $ \langle 1, -2, 5 \rangle $


$x-2 y+5 z=0$

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Video Transcript

Hello. So the question is belong to directors and geometry of the space. And the question is find an equation of the plane. The plane passes to origin and perpendicular to director 1- to fight. So the equation yeah of playing passing through. Yeah, yeah 0010. And yeah, perpendicular to the victor 1 -2.5. Can be. Have you done ass AX -10 plus B by minus y zero plus. See that minus that you for X zero y zero. There's you are the point to which the plane passes and abc other normal electric points. So those are one in two x minus zero plus minus of two by minus you plus five, dead minus zero. That will be equal to zero. So that equation becomes x minus two By Plus five is equal to zero. It is the required equation of plane that passes through the region and normal to director 1- to find hope. This clears your doubt.