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# Find an equation of the plane.The plane through the origin and perpendicular to the vector $\langle 1, -2, 5 \rangle$

## $x-2 y+5 z=0$

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Hello. So the question is belong to directors and geometry of the space. And the question is find an equation of the plane. The plane passes to origin and perpendicular to director 1- to fight. So the equation yeah of playing passing through. Yeah, yeah 0010. And yeah, perpendicular to the victor 1 -2.5. Can be. Have you done ass AX -10 plus B by minus y zero plus. See that minus that you for X zero y zero. There's you are the point to which the plane passes and abc other normal electric points. So those are one in two x minus zero plus minus of two by minus you plus five, dead minus zero. That will be equal to zero. So that equation becomes x minus two By Plus five is equal to zero. It is the required equation of plane that passes through the region and normal to director 1- to find hope. This clears your doubt.

IIT(BHU), Varanasi

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