Question
Find an equation of the straight line tangent to the given curve at the point indicated.$$y=\sqrt{5-x^{2}} \text { at } x=1$$
Step 1
We substitute x=1 into the equation of the curve to get: \[y=\sqrt{5-1^{2}}=\sqrt{4}=2\] So, the point is (1,2). Show more…
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