Question
Find an equation of the tangent line to$$f(x)=2 \ln x^{3}$$
Step 1
We can do this by substitifying x=1 into the function $f(x)=2 \ln x^{3}$. This gives us $f(1)=2 \ln 1^{3}=2 \ln 1=0$. So, the point is (1,0). Show more…
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