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Find an equation of the tangent line to the curve at the given point.$ y = 2x^3 - x^2 + 2, (1,3) $

$$y-3=4(x-1) \text { or } y=4 x-1$$

01:08

Frank L.

Calculus 1 / AB

Chapter 3

Differentiation Rules

Section 1

Derivatives of Polynomials and Exponential Functions

Derivatives

Differentiation

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he had clear. So when you right here. So the tangent line at point. A bee has slope m equals D Y over DX access equal to a and the form of the equation we use is gonna be point slope, which is why minus B equals m times X minus a. So we have m, which is our derivative d over d x of two X cubed minus X square plus two when X is equal to one and this gives for so the line equation is why minus three is equal to four terms X minus one, which is equal to four x minus one.

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