00:01
When given a parametric curve, x equals t to the fourth plus one, y equals tq plus one.
00:12
And we're asked to find the equation for the tangent line when t not, when t is minus one.
00:25
So to find the tangent line to a parametric curve or find the slope of this parametric curve, we can write dy, dx as dy v .t, divided by, dx dt.
00:35
Now that's, you can't just say that these cancel out, but you know, they talk about that in the book.
00:42
That it's really the chain rule that allows you to do that because dy, d.
00:46
Y, d .t equals d y, d x, d x, d x, t, and then you can solve for d y, d x, x, so we need to take d y, dt, t, that just becomes 3t squared.
00:57
D x, d x, t is 4t to the f cubed.
01:01
So the slope winds of being 3 over 4t...