00:02
All right, so equation of a tangent line.
00:06
What you need is a point and a slope.
00:10
So if you get in the equation, it makes perfect sense then that you can use point slope form to find a tangent line.
00:18
So they give you the point already is 0 .1.
00:23
And let's see, i would write it this way.
00:27
To find the slope, you need, d, y, dx, when at the ordered pair, 01.
00:34
And once you find that, then you can get the answer.
00:38
So they give you the equation x, e to the y.
00:43
So this is going to be implicit differentiation, the way it's set of y, e to the x is equal to 1.
00:51
And each one of these is the product rule, where the derivative of x is one, leave e to the y alone, plus leave x alone.
01:00
The derivative of e to the y is e to the y times d, y, y, d, y, y, x.
01:04
And then plus the derivative of y is d y d x e to the x power plus leave y alone the derivative of e to the x is e to the x is equal to zero so what's nice about this is anywhere you have x is zero like right here that'll equal zero so i'm going to ignore that piece as i'm looking at this you will you have to be careful because e to the zero power is equal to one so that's just d -y -d -x times one.
01:40
And this is another, you know, one times one.
01:44
So that's plus one there.
01:45
And then e to the first power is equal to e...